Riddle...

Here is the email passed by one of my friends. It's quite fun I think... Let's get started...

A man wanted to get into his work building, but he had forgotten his code. However, he did remember five clues. These are what those clues were:

The fifth number plus the third number equals fourteen.
The fourth number is one more than the second number.
The first number is one less than twice the second number.
The second number plus the third number equals ten.
The sum of all five numbers is 30.

What were the five numbers and in what order?

For those who do not receive the email contains the same riddle from me, will reveal the answer by next week... =P

Have Fun in solving the riddle...

Lin ^ ^

(Taken from http://linda_tan.blogs.friendster.com/4nswer_me/)

For answer, view the above link next week, I am so lazy to post out the answer =P

Answer (From Ms Huat Huat, taken from her blog....)

Take the 5 numbers as: a, b, c, d, e

Based on the clues:
e + c = 14
d = 1 + b
a = 2b – 1
b + c = 10
a + b + c +d + e = 30

… to make it easier let’s make every number has the same variable (this case take ‘b’ as the standard)

a = 2b -1
c = 10 – b
d = 1 + b
For e, 14 – e = c in which, c = 10 – b, substitute these 2 formula
14 – e = 10 – b
4 = e – b
e = 4 + b

The substitute all the formulas above to
a + b + c +d + e = 30
(2b-1) + b + (10–b) + (1+b) + (4+b) = 30
4b + 14 = 30
4b = 16
b = 4

a = 2b – 1
a = 7

c = 10- b
c = 6

d = 1 + b
d = 5

e = 4 + b
e = 8

Now, the man can enter the office with this code: 74658

Some might have more effective way in solve this riddle, anyway, as long as it can let the man enter the office, it should be fine. Haha =P